Amp Calculator — Watts, kW, kVA and HP to Amps
Electrical & EnergyConvert watts, kilowatts, kVA or motor horsepower to amps — or amps back to watts — for DC, single-phase and three-phase circuits.
Last updated: October 2026
Current (amps), voltage (volts) and power (watts) are linked: for a DC circuit, watts = volts × amps. This amp calculator applies that relationship for DC, single-phase AC and three-phase AC. It includes power factor for AC loads and efficiency for motors. For AC, power factor matters. A resistive load such as a heater or incandescent bulb has a power factor of 1, so amps = watts ÷ volts. Motors, compressors and many electronic power supplies draw more current than their watt rating suggests. Their power factor is below 1, so divide by it as well. Three-phase circuits spread the load across three conductors, which brings in a factor of √3 (about 1.732) when you use the line-to-line voltage. If you know apparent power in kVA (common on transformers and generators), power factor doesn't apply: current = VA ÷ volts (÷ √3 for three-phase). For a motor rated in horsepower, the calculator converts output HP to the electrical input power using the efficiency you enter.
How to Convert Watts to Amps
1. Choose the system: DC, single-phase AC, or three-phase AC. For three-phase, use the line-to-line voltage (e.g. 208, 480). 2. Convert the power to watts: kW × 1,000; HP × 746 ÷ efficiency for a motor's electrical input. 3. DC: amps = watts ÷ volts. 4. Single-phase AC: amps = watts ÷ (volts × power factor). 5. Three-phase AC: amps = watts ÷ (√3 × volts × power factor). For kVA, skip the power factor: amps = VA ÷ (√3 × volts).
Formula
DC: I = P ÷ V Single-phase: I = P ÷ (V × PF) Three-phase: I = P ÷ (√3 × V_LL × PF) From apparent power (AC): Single-phase: I = S ÷ V Three-phase: I = S ÷ (√3 × V_LL) Motor input: P = HP × 746 ÷ Efficiency I — current (A) P — real power (W) S — apparent power (VA) V — voltage (V) V_LL — line-to-line voltage PF — power factor (0–1)
Amp Calculation Examples
Example 1 — 1,800 W space heater on 120 V
Resistive load, PF = 1 I = 1,800 ÷ 120 = 15.0 A
Example 2 — 10 kW three-phase load at 480 V, PF 0.9
I = 10,000 ÷ (1.732 × 480 × 0.9) = 10,000 ÷ 748.2 = 13.37 A per phase
Example 3 — 75 kVA transformer secondary, 208 V three-phase
I = 75,000 ÷ (1.732 × 208) = 75,000 ÷ 360.3 = 208.2 A full-load current
Practical Notes
- › For sizing conductors, take the current from here to the wire size calculator. It checks ampacity and voltage drop.
- › Nameplate current beats a calculated value. Motors and appliances list full-load amps on the nameplate, and that is what you should design to.
- › To see what a load costs to run, enter its watts in the energy cost calculator.
- › In the US, 120 V and 240 V are nominal. Actual supply voltage varies, and lower voltage means higher current for the same power.
Watts to Amps at Common Voltages (PF = 1)
| Watts | 12 V DC | 120 V | 240 V | 208 V 3φ | 480 V 3φ |
|---|---|---|---|---|---|
| 100 | 8.3 A | 0.83 A | 0.42 A | 0.28 A | 0.12 A |
| 500 | 41.7 A | 4.17 A | 2.08 A | 1.39 A | 0.60 A |
| 1,000 | 83.3 A | 8.33 A | 4.17 A | 2.78 A | 1.20 A |
| 1,500 | 125.0 A | 12.50 A | 6.25 A | 4.16 A | 1.80 A |
| 2,000 | 166.7 A | 16.67 A | 8.33 A | 5.55 A | 2.41 A |
| 5,000 | 416.7 A | 41.67 A | 20.83 A | 13.88 A | 6.01 A |
| 10,000 | 833.3 A | 83.33 A | 41.67 A | 27.76 A | 12.03 A |
Computed from the formulas above with power factor 1 (resistive load). Loads with a lower power factor draw proportionally more current.
Assumptions & Limitations
What this calculator assumes
- Steady-state, sinusoidal AC with balanced three-phase loads. Three-phase results are per-phase line current.
- Power factor is entered by you. It is 1 for resistive loads; for motors and electronic loads, use the nameplate or datasheet value.
- Horsepower is mechanical output, converted at 746 W per HP and divided by the efficiency you enter to get electrical input.
- Voltage is the actual supply voltage at the load.
Not included
- Motor branch-circuit sizing. In the US, the NEC sizes motor circuits from its full-load current tables (Article 430), not from nameplate horsepower math.
- Inrush or starting current, harmonics, and unbalanced three-phase loads.
- Breaker or fuse selection and conductor sizing.